Splet$\begingroup$ This answer is correct, but the underlying reasoning is likely to be unclear to an introductory student (presumably the target audience here). The second line ($0.5mv^2=mgh$) looks like conservation of energy, but it's not clear why you're allowed to go from there to the next step, where you use just one component of the velocity. SpletThe ball will achieve the maximum height when it is thrown vertically upward. For such motion, the final velocity v is zero at the maximum height H. Acceleration, a = –g Using …
SOLUTION: if a ball is thrown directly upward with a velocity of 20 ...
SpletA cricket ball is thrown by a player at a speed of \(20\) m/s in a direction \(30^\circ\) above the horizontal. The maximum height attained by the ball during its motion is: (Take\(g=10\) m/s2) 1. \(5\) m 2. \(10\) m 3. \(20\) m 4. \(25\) m NEET 2024 Exam Paper - Ganganagar Practice questions, MCQs, Past Year Questions (PYQs), NCERT Questions, Question … Splet26. jul. 2024 · at t = 2.00 s the y coordinate of the ball was zero. (As usual, we say the ball starts off at y = 0.) (b) We know that at maximum height the velocity v is zero. We can use. so the maximum height attained by the ball was 4.90 m. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series marvel soulmate buzzfeed quiz
A ball thrown vertically upward is caught by the thrower ... - Sarthaks
Splet20. okt. 2015 · Here you have a parabolic function that opens downward modeling the height of the ball. The maximum height will be achieved at the vertex, since after that the ball starts falling back down, so we need to find the vertex! Rearranging the equation into a standard form gives us: y = -16t 2 + 22t + 0 SpletHeight attained by the ball, h = 10 m. Time taken to attain maximum height, t =? Step 2: Calculating the initial velocity of the ball. Applying 3rd equation of motion for the freely falling object, v 2 = u 2 + 2 g h ⇒ 0 = (u) 2 + 2 × (-10 m s-2) × 10 m u = 10 2 m s-1 [ ' g ' is negative when a body is projected upwards] Step 3: Calculating ... Splet11. sep. 2024 · Given Initial velocity of ball, u=49 m/s Let the maximum height reached and time taken to reach that height be H and t respectively. Assumption: g=9.8 m/s2 holds true (maximum height reached is small compared to the radius of earth) Velocity of the ball at maximum height is zero, v=0 v2−u2=2aH 0− (49)2=2× (−9.8)×H H=122.5 m v=u+at … marvel solicits april 2022