How many 176 resistors are required
WebJun 17, 2016 · Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω. 1/44 = 1/176 + 1/176 + 1/176 .....χ times. 1/44 = x / 176 => x = 176/ 44 => x = 4. Therefore, 4 resistors of 176 Ω are required to draw the given amount of current. I hope, this will help you___ . Thank you WebApr 30, 2024 · 4 Resistors are required. Step-by-step explanation: Given: Volts = 220 Volts. Current = 5 Ampere. Resistance of each resistor, R = 176 Ohms. No of resistors = n. We know that: v = RpI. ∴ ∵ . Taking N to the other side we …
How many 176 resistors are required
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WebMar 29, 2024 · (a) For highest resistance according to question resistances must be connected in series: 4 Ω, 8 Ω, 12 Ω, 24 Ω R 1 = 4 Ω R 2 = 8 Ω R 3 = 12 Ω R 4 = 24 Ω Total resistance in series = R 1 + R 2 + R 3 + R 4 = 4 + 8 + 12 + 24 = 48 Ω Now, resistance is maximum when connected in series. WebApr 8, 2024 · Complete step by step answer: We have given here to find the number of \ [176\Omega \] resistors needed to carry \ [5A\] on a \ [220V\] line. Let, the number of resistors needed is \ [x\]. Hence, the equivalent resistance of the \ [x\] number of resistors will be when connected in parallel,
WebMar 14, 2024 · Hence using the Ohm’s law and the value of resistance from equation (1), we get: V = I R n e t ⇒ 220 = 5 ( 176 N) ⇒ N = ( 176 44) ⇒ N = 4. Hence, 4 of the 176 Ω resistors in parallel would be required to get a net current of 5A flowing through a 220V line. WebOct 3, 2024 · We know that according to Ohm’s Law, V = IR. Therefore, R = V/I = 220/5 = 44ohm. Now since n such resistors are connected in parallel,so. 1/R = n/176. or, 1/44 = …
WebNow, as per Ohm’s Law, we get, V I = 176 x V I = 176 x ⇒ x = 176×5 220 = 4 x = 176 × 5 220 = 4 Hence, in order to draw the required amount of current, four 176 Ω resistors will be … WebI ( current ) = V (voltage ) / R ( resistance ) . hence to carry 5A at 220 V supply Resistance required V / I = 220 / 5 = 44 OHMS. In parallel circuit 1/R = 1/R1 + 1/ R2 + 1 / R3 so on …. Hence 1 / 44 = n / 176 when n = no of parallel resistance so n = 176 / …
WebR_total = (R1 * R2) / (R1 + R2) Where R1 and R2 are the values of the two resistors. To calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula:
WebQuestion From - NCERT Physics Class 10 Chapter 12 Question – 033 ELECTRICITY CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-How many `176 Omega` resistors (in... great southern conyers gaWebApr 8, 2024 · Hint: The equation for the net resistance for two resistors of resistances connected in parallel hast to be used first. Further, Ohm's law and Kirchoff’s current law will also be used to find the number of resistors. Formula used: The net resistance for two resistors of three resistances \[({R_1}),({R_2})\]and \[\left( {{R_3}} \right)\] connected in … florence best hotelsWebApr 5, 2024 · Therefore, current through 12 Ω resistor = 0.67 A. 12. How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Suppose n resistors of 176 Ω are connected in parallel. 1/R = 1/176 + 1/176 + ……….n times 1/R = n/176 or R= 176/n Ω By Ohm’s law R=V/I 176/n = 220/5 n= (176 x 5)/220 = 4 13. florence bixby elementaryWebTo calculate the number of 176 ohm resistors required in parallel to achieve a specific resistance, you need to use the following formula: N = R_desired / R_single Where N is the … florence bixbyWebApr 29, 2024 · Q 10: How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? From Ohm’s law, ∴four resistors of 176 Ω are required to draw the given amount of current. When three equal resistance are connected in parallel the effective resistance is 1 by 3 home if all are connected in series the effective resistance is? florence bixby elementary long beachWebMar 19, 2024 · For three resistors if we connect them in parallel the equivalent resistance is R 1 R = 1 R1 + 1 R2 + 1 R3 1 R = 1 R 1 + 1 R 2 + 1 R 3 For x number of resistors of resistance 176 Ω the equivalent resistance of the resistors connected in parallel is given by ohm’s law as V = IR R = V I V I Where,supply voltage, V = 220 V current I = 5A florence best steak restaurantWebMar 30, 2024 · NCERT Question 10 How many 176 Ω resistors (in parallel) are required to carry 5 A on a 220 V line? Current = I = 5 A Potential difference = V = 220 V Resistance of … great southern cricket association fixtures