WebFind all indexes Strings in a Python List which contains the Text. In the previous example, we looked for the first occurrence of text in the list. If we want to locate all the instances or occurrences of text in the string, then we need to use the index () method multiple times in a loop. During each iteration, pass the start index as the ... WebJan 5, 2016 · Using python-docx you can then retrieve font information. Here's an example of getting all the bold text. from docx import * document = Document ('/path/to/file.docx') for para in document.paragraphs: for run in para.runs: if run.bold: print run.text. If you really want to use PDFMiner you can try this. Passing '-t' would convert the PDF into ...
If else statement for finding the index of a character in a string
WebNov 6, 2014 · I am having a set of text fields where i am doing validation Say I am Having a field called "seats" this can accept value less than "99999".Meaning I should not able to enter the "99999" any thing less than that is ok. For that I wrote below if and else if . please tell me whether I am doing any thing wrong. I am confused a lot from morning ... Webif condition1: # code block 1 elif condition2: # code block 2 else: # code block 3. Here, If condition1 evaluates to true, code block 1 is executed. If condition1 evaluates to false, then condition2 is evaluated. If condition2 is true, code block 2 is executed. If condition2 is false, code block 3 is executed. Working of if...elif Statement fanfiction general hospital
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WebHere's the rules: use grep to find patterns and print the matching lines, use sed for simple substitutions on a single line, and use awk for any other text manipulation.grep and sed were both created to simplify and are named based on common uses of the old text editor ed - grep is named after g/re/p which are the ed commands to find a regexp and print … WebThe IF function is one of the most popular functions in Excel, and it allows you to make logical comparisons between a value and what you expect. So an IF statement can have … WebApr 30, 2024 · depending on your phrases the test may be more efficient this way: def test (string): s = string.split () if any (word in Group_A for word in s) and any (word in Group_B for word in s): return 1 else: return 0. Oh it should return 0 as well :D But I think your answer has solved my problem already haha. cork to lanzarote flights